How many integers in the set {100, 101, 102, ..., 999} have at least one digit repeated?

Solution

Total number of numbers from 100 to 999 = 900

The number of three digits numbers with unique digits:

_ _ _

The hundredth's place can be filled in 9 ways ( Number 0 cannot be selected)

Ten's place can be filled in 9 ways

One's place can be filled in 8 ways

Total number of numbers = 9*9*8 = 648

Number of integers in the set {100, 101, 102, ..., 999} have at least one digit repeated = 900 - 648 = 252

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How many integers in the set {100, 101, 102, ..., 999} have at least one digit repeated?

Question Description
How many integers in the set {100, 101, 102, ..., 999} have at least one digit repeated?Correct answer is '252'. Can you explain this answer? for CAT 2022 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about How many integers in the set {100, 101, 102, ..., 999} have at least one digit repeated?Correct answer is '252'. Can you explain this answer? covers all topics & solutions for CAT 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many integers in the set {100, 101, 102, ..., 999} have at least one digit repeated?Correct answer is '252'. Can you explain this answer?.

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This question is from Permutation and Combination. From a set of integers, we need to find the numbers of integers that have at least one digit repeated. CAT Permutation and Combination and Probability is an important topic in the CAT Exam. A range of questions can be formed from this topic. In CAT Exam, one can generally expect to get 2~3 questions from these topics.

Question 16 : How many integers in the set {100, 101, 102, ..., 999} have at least one digit repeated?

Correct Answer: 252


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Explanatory Answer

The total number of integers from 100 to 999 is 999 - 99 = 900.
Of these 900 integers, if we could find the number of integers which do not have repetitions in them, we can also find the number of integers that have repetitions.

Let's find the number of integers that between 100 and 999, which do not have repetitions.

  a b c
Possibilities 1 to 9 0 to 9
except a
0 to 9
except a and b
Number of
Possibilities
9 9 8

The number of integers that between 100 and 999, which do not have repetitions = 9 × 9 × 8
Therefore, the number of integers that have repetitions = 900 - 9 × 9 × 8
= 9 (100 - 9 × 8)
= 9 (28)
= 180 + 72 = 200 + 52 = 252


The question is "How many integers in the set {100, 101, 102, ..., 999} have at least one digit repeated?
"

Hence, the answer is, "252"

How many integers in the set 100 101 102 999?

How many integers in the set {100, 101, 102, ..., 999} have at least one digit repeated? Solution: The given set is a set of all three-digit numbers and the number of numbers in the set =900.

How many integers are there between 100 and 1000?

Now, there are 899 numbers between 100 and 1000.

How many positive integers are there between 100 and 999 both included that are divisible by 3 or 4?

So there are 75 numbers in between 100 and 999 inclusive that are divisible by 3 or 4.

How many numbers from 1 to 100 are there each of which is exactly divisible by 6 but also contain 6 as a digit in it?

∴ The required numbers are 4, 24, 40, 44, 48, 64, 84. Clearly, there are 7 such numbers.