Which smallest number should divide 1188 so that the quotient is a perfect cube?

The primes 2 and 11 do not appear in groups of three. So, 1188 is not a perfect cube. In the factorisation of 1188, prime 2 appears only two times and the prime 11 appears once. So, if we divide 1188 by 2 × 2 × 11 = 44, then the prime factorisation of the quotient will not contain 2 and 11.

Hence the smallest natural number by which 1188 should be divided to make it a

And the resulting perfect cube is 1188 ÷ 44 = 27 (= 33).

What should be divided to make 1188 a perfect cube?

So, if we divide 1188 by 2 × 2 × 11 = 44, then the prime factorisation of the quotient will not contain 2 and 11. Hence the smallest natural number by which 1188 should be divided to make it a perfect cube is 44. And the resulting perfect cube is 1188 ÷ 44 = 27 (=33 ).

What is the smallest number that must divide 1188 to make it a perfect cube?

118844 = 27 = 33.

IS 118 a perfect cube if not by which smallest number should 118 be divided so that the quotient is a perfect cube?

Expert-Verified Answer 44 is the smallest natural no. so that quotient will become perfect cube...

Is 8640 is a perfect cube?

8640 is not a perfect cube.